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Here's my take on this one :

[ There aren't any tie games possible in the World Series  ]

We play 6 games  and we want the Giants  to win any 4 of them

So we have

C(6,4) (1/2)^6  =  15 / 64

Of course.......this is the same probability that the Royals win in 6 games, as well

There are two answers.

5 ± √36     =     5 ± 6     =     5 + 6     or     5 - 6     =     11     or     -1

i dont understand the last two steps can u pls explain

 

61=  1.05F + 17.64     subtract  17.64 from both sides

43.36   =  1.05 F     divide  both sides by 1.05

≈ 41.3  =  F

WolframAlpha  gives  the minimum natural solution  of  x = 204 [ and y  = 60 ]

Hi Geno

It is nice to see you.

That is what I thought but it could be that the 6 was meant to be a 7 in which case it would still be half.

or that we were suppose to include the possibility of a tie, whch would make the problem a tad harder.

Say we were meant to include the possibility of a tie.

Then the outcomes culd be 2:4,   4:2,   or  3:3

I do not think it could be 1:5 or 0:6 because then the series would have finished earlier.

The number of ways a team can win 2 games in 6 is 6C2  =  15

The number of ways a team can win 3 games in 6 is 6C3 =  20

The number of ways a team can win 4 games in 6 is 6C4 = 15

So the probability that they score 3 games each is      20/50 = 4/10

The remaining possibilities are split equally between A and B wining    0.5(1-0.4) = 0.3

So if they play 6 games the probabilities are 

P(tie) = 0.4

P(A wins) = P(Bwins) = 0.3

It does not exactly mean window but it can resemble a window. The digit 1 can be written as a vertical line and the + can be written to represent the wood dividers for the glass planes. If you put that all together it resembles a window.

    Why don't you go try it? 

Or you can stare at this image. ;-)

I'm sorry, but there was a typo in the first answer posted. 14.8 x 5 = 74 

Here is a list to help you get started with this kind of multiplication.

14.8 x 5 = 74

14.8 x 10 = 148

14.8 x 15 = 222

14.8 x 20 = 296

14.8 x 30 =444

14.8 x 35 = 518

14.8 x 40 = 592

So hopefully by now, you can see a pattern. Simply skip count by fives and multiply times 14.8 and you will get a whole number each time!

My computer gives x =-7,310 and y= 86

Note that 14.8 can be written as 14 + 4/5 =74/5

74/5  x 5/74 (its reciprocal and any multiples of its reciprocal, 10/74, 15/74, 20/74......etc. will give you all natural numbers from 1, 2, 3, 4........etc.). 

If  f(x)  =  [x + 1/x - 1]³,  f(x)  is of the form  f(x) = [g(x)]³, so  f'(x)  =  3[g(x)]²·g'(x)

  f(x)  =  [x + 1/x - 1]³     --->     f'(x)  =  3[x + 1/x - 1]³·[1 - 1/x²]

To find f'(2), replace x with 2 in the above derivative, and simplify.  

Remember...

\(\frac{d}{dx}u^3 \,=\, 3u^2\,\cdot\,\frac{d}{dx}u\)

So

 \(f'(x)\,=\,3[x+\frac1x-1]^2\,\cdot\,\frac{d}{dx}[x+\frac1x-1] \\~\\ f'(x)\,=\,3[x+\frac1x-1]^2\,\cdot\,[\frac{d}{dx}x+\frac{d}{dx}\frac1x-\frac{d}{dx}1] \\~\\ f'(x)\,=\,3[x+\frac1x-1]^2\,\cdot\,[1-x^{-2}]\)

To find  f'(2) , plug in  2  for  x .

\(f'(2)\,=\,3[2+\frac12-1]^2\,\cdot\,[1-2^{-2}] \\~\\ f'(2)\,=\,3[\frac32]^2\,\cdot\,[1-\frac1{4}] \\~\\ f'(2)\,=\,3[\frac94]\,\cdot\,[\frac3{4}] \\~\\ f'(2)\,=\,\frac{81}{16}\)

( If   f(x)  is meant to be  \([\frac{x+1}{x-1}]^3\)  then you get a different answer. )

For the equation  x + 3y  =  -8

                                  3y  =  -8 - x

                                    y  =  (-8 - x) / 3

When  x = 0,  y = -8/3.

For any positive value of x, y will be smaller than  -8/3.

So, the range of y is:  y  <=  -8/3.

If you multiply 14.8 by 5, you will get 64, a whole number.

My understanding of the problem is, even though the series could last 7 games, in this case it lasted only 6 because one of the teams achieved its fourth win in the sixth game.

Since each team has a 1/2 probability of winning each game, each team will have a 1/2 probability of winning the series (this does not depend upon how many games the series actually lasts).

So, the probability that the Giants win is 0.50  (one-half).

I don't understand the question.

the series last 6 games is that whether or not anyone has won yet?

So maybe a team won or maybe no-one won?

If a team did win then the chance of it being either team is 50%. I mean 50% each.........

I guess you must mean that maybe no team won?

What about it?

The answer is...

126623672723911929137723922139172.4264346160941511*(infinity)

The Giants and the Royals each have a 50% or 1/2 chance of winning each game. To win the series you must win 4 games out of 7. There are 2 possible outcomes for each of the individual games. 2*2*2*2*2*2*2= 128 possible outcomes.

     This may be wrong because you said 4 out of 6 games, but then it is possible for a 3-3 tie to appear, so I solved the problem with the possible games played being 7.

The simple answer is that \(0/0 \) is undefined.

m  =  slope  =  \(\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{-2-1}{-3-0}\,=\,\frac{-3}{-3}\,=\,1\)

Using the point  (0, 1), the equation in point-slope form is

y - 1  =  1(x - 0)      Simplify

y - 1  =  x               Add  1  to both sides.

y  =  x + 1              This is the equation in  y = mx + b  form.

We first start by multiplying the A in front of the problem times every other item inside the parenthesis. So, \(a\times a + a\times 2\) = \(a^2 + 2a\)

Thanks guest,

That is a good resource :)

The first video explains why it is NOT 1 and NOT 0

But the video is GOOD so thank you Owlface  for giving the address.    

The second video is probably goopd too but I have not watched it :)

0/0 is undefined.