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(x+7)(x-14)= 0   so x =-7 and 14

Quadratic Formula for solving quadratic equations in the for  ax^2 +bx + c = 0 :

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

wait so what is number one, and no i dont know the quadratic equation

1 Do you know how to use the quadratic formula?   x^2 -7x-98 = 0

2 x^2 -48 = 2x       x^2-2x-48=0     (x-8)(x+6)    so x = 8 or -6

3   expand   x^2-12x+32-12 = 0

                   x^2-12x+20 = 0     use quadratic formula or just factor it to (x-10)(x-2) = 0    so x = 10 or 2

4  x^2-x-72

5 t^2 = 324    so t = + or - sqrt 324 = +-18

h= k v^2

8 = k (20)^2

k = 8/(20^2) = 8/400 = 1/50 = .02

When v = 35

h = .02 (35^2) =  24.5 m

Longest side is 3 x 12 = 36

Middle side is   2 x 12 = 24

Shortest side is 1 x 12 = 12

\(\sum \limits_{k=1}^{40}~2k-1 = \\ \left(2\sum \limits_{k=1}^{40}~k\right) - 40 = \\ 40\cdot 41-40 = 40^2 = 1600\)

Surprisingly, NO!

8-c/4=-6       add 6 to both sides

14-c/4 = 0     add c/4 to both sides

14 = c/4       Multiply both sides by 4

56 = c

y = k / x

7 =k/9  

so k = 63

y=63/x

y = 63/21 = 3

As you can see!

\(a_n = a_1 + (n-1)d\\ a_5 = a_1 + 4d = 9\\ a_{32} = a_1 + 31d = -84\\ \text{subtract }a_5 \text{ from }a_{32}\\ 27d=-93\\ d=-\dfrac{93}{27} = -\dfrac{31}{9}\\ a_1 = 9-4d = 9-4\left(-\dfrac{31}{9}\right) = \\ 9+\dfrac{124}{9} = \dfrac{205}{9}\\ a_{23} = a_1 + 22d = \dfrac{205}{9}+22\left(-\dfrac{31}{9}\right) = -53 \)

No! It’s much funnier telling Rom after the fact!..........................

Yeah, I agree. This isn't the best place to put this post, but you are definitely right.

Excuse me, this is not a place to post anything about video games unless is it labeled "off-topic." Please remove this. (i have to admit though, i do like video games.)

1-

V=Length x Height x Width
Length = a
Height = a
Width =2a
432 =a^2 * 2a
432 =2a^3
a^3 =432 / 2
a^3 =216             Take the 3rd root of both sides:
a = 216^(1/3)
a = 6 ft. the length and the height of the rectangular prism.
Width =6 x 2 = 12 ft. the width of the rectangular prism.

y=kx

30 = k* 6     

  so   k=5

so y = 5x     

  when x= 12   

y = 5*12 =60

ZERO solutions

4x+5 = 9+4x       subtract 4x from BOTH sides

5=9       this obviously is not true....no solutions

... 

Amplitude will be  ONE because there is no multiplier in front of   cos 4x

period will be 1/4 of original   =   pi/2

My bad, I probably should've said thatI figured this out. I'm sorry that I made you do all of that work >.<

20000(1.08^t) = growth

1700(.93^t) = decay

If the object of the exponent > 1  it is growth

if object of the exponent is a fraction between 0 and 1   it is  decay

Does that help?

You're welcome.....