All Answers 358087 Answers

min only takes two arguments, so you can handle min(a,b,c) as follows: min(a, min(b,c))

Sorry anon but you have found the mean (average)  NOT the median (middle)

-7,-1,0,8,4,2,-7, 2

line them up in oder

-7,-7,-1,0,2,2,4,8

The median is the middle score.  Here there are 2 middle scores so the median will be the averagae of them.

median=(0+2)/2=2/2=1

The median is 1

$${\frac{\left({\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,-\,}}{\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0}}\right)}{{\mathtt{8}}}} = {\frac{{\mathtt{1}}}{{\mathtt{8}}}} = {\mathtt{0.125}}$$

   $$\small{\text{
c and a ?
$
\boxed{
\; ac = \dfrac{2A}{\sin{(B)}} \qquad a=4-c \qquad A= \frac{3}{4}\sqrt{3} \qquad \sin{(B)}=\frac{\sqrt{3}}{2}\;
}
$
}}\\\\\\
\small{\text{
$
(4-c)c = 2*\dfrac{3\sqrt{3}}{4}*\dfrac{2}{\sqrt{3}}= 3$
}}\\\\
\small{\text{
$
c^2-4c+ 3 =0 \qquad
$
}}
\small{\text{
$
c_{1,2}=\dfrac{
4\pm\sqrt{16-4*3 }
}
{2}
= \dfrac{ 4\pm \sqrt{4} } {2}
= \dfrac{ 4\pm 2 } {2}
=2\pm 1
$
}}\\\\
\small{\text{
$
c_1= 2+1 \quad \boxed{c_1=3} \qquad c_2= 2-1 \quad \boxed{c_2= 1}$
}}\\\\
\small{\text{
$
a_1=4-c_1 \qquad a_1=4-3 \qquad \boxed{a_1=1}$
}}\\
\small{\text{
$
a_2=4-c_2 \qquad a_2= 4-1 \qquad \boxed{a_2=3}$
}}$$

(4^2)^8=4^16

$$7(e+3)=42$$

$$7e+21=42$$

$$7e+21(-21)=42(-21)$$

$$7e=21$$

$$e=3$$

Inverse sine is the same as arc sin

So just enter  asin(0.2308)   on the calculator (on the home page)

An = 2(-3^n)+5^n

$$\\A_n = 2(-3^n)+5^n\\\\
A_0 = 2(-3^0)+5^0=2*1+1=3\\\\
A_1 = 2(-3^1)+5^1=2*-3+5=-1\\\\
A_2 = 2(-3^2)+5^2=2*-6+25=13\\\\
etc$$

Here is a whole list of sites that could help you :)

From conservation of energy, the kinetic energy at take off equals the potential energy at the top of the jump, which is just mgh:  7.2*9.8*1.2 Joules

$${\mathtt{Energy}} = {\mathtt{7.2}}{\mathtt{\,\times\,}}{\mathtt{9.8}}{\mathtt{\,\times\,}}{\mathtt{1.2}} \Rightarrow {\mathtt{Energy}} = {\mathtt{84.672}}$$  Joules

.

log₁₀₀₀x = -2/3 means x = 1000^-2/3 or x = (1000^1/3)^-2 or 10^-2 or 1/10² or 1/100

.

log₂(-4) = x  means that 2^x = -4.  However, with any real number x, 2^x will never be negative, so d is the right response.

.

General rules:  log(a*b) = log(a) + log(b)  and log(a^b) = b*log(a)

So:

log(12) = log(4*3) = log(4) + log(3) = log(2²) + log(3) = 2*log(2) + log(3)

log(9/2) = log(9) - log(2) = log(3²) - log(2) = 2*log(3) - log(2)

log(3⁵) = 5*log(3)

I'll leave you to fill in the values for log(2) and log(3)

.

Almost certainly the calculator does not calculate Pi. That number is most likely stored in ROM so it can be recalled instantly. It is probably stored to 1 or 2 more significant figures than the display shows.

Tn=15-7(n-1)

@@ End of Day Wrap   Tues 10/2/15   Sydney, Australia   Time 7:20 pm ♪ ♫

Hello everyone,

Today our great answers were supplied by Takahiromaeda, Sasini, Variablenumbers, CPhill, cjohns25, Tetration, BrittanyJ, Fireshot360, Heureka, YocenatheRipper, mahum, Mathematician, saseflower, minee, Jillybean, xXSwagMasterXx, and our Princess Kitty<3,

Thanks all.

Interest posts:

Wed 11/2/15

You will get you answer quicker if you google it. 

Use change of base rule

Or if you are doing it on the web2 calc you don't even have to.  It will work it out in any base:))

Use the change of base rule.

I you do not know what this is look it up in formulary.

What about it?

Mathematician, a kite is NOT a rhombus!

However, you can find their areas the same way

A=half the product of the diagonals.

see if this helps.

You can use change of base law

$$log_xy=
\frac{log_{10}y}{log_{10}x}$$

FV=P(1+r)^n

so

Int=P(1+r)^(n)   -P

If $2000 is invested for 4 years and interest is 5%p.a. accumulated daily then

P=2000

r=0.05/365

n=4*365