All Answers 356763 Answers

Hey, I'm not going to be rude but can you leave your problems up instead of editing and deleting it after someone answers it? Thank you!

Lets write this in a mathy way so this is easier to see.

6^1/2-5^1/2 =  

0.2134217652833884

This is an irrational number and can't be comverted to a fraction(I think)

Ten carbon atoms, 15 hydrogen atoms and 1 nittogen atom

Just post actual math question tho :P

I+I I guess 

(1/5)*(3/4)=

3/20

You multiply the numinators together and you multiply the denominators together!

Solve for k.

𝑚 = −15𝑗 − 6𝑘 − 8      add 15j  and 8 to both sides

m + 15j + 8  = 6k      divide both sides by 6

[ m + 15j + 8 ] 

____________         =  k  

        6

Solve for t.

7 + 𝑧 = 6𝑡 − 8𝑛 − 15          add 8n    and 15 to both sides

[7 + z + 8n + 15  ]   =  6t        divide both sids by 6

[7 + z + 8n + 15  ]     =   t

______________

           6

−32 > −5 + 9𝑥        add 5 to both sides

-27  >  9x               divide both sides by 9

-3  >  x

𝑥 − 7.67 ≤ 9.4         add 7.67 to both sides

x ≤  17.07

[1/2] 𝑥 ≤ − 4/7        multiply both sides by 2

x ≤ - 8/7

Hey, TR.....good to see you......!!!!

12, since -7 is multiplied by an invisible negative one.

Since  25 is a power of 5, the key here is to see if we can equate bases.....

25^x  = 1/5             note that 25  = 5²    and  1/5  =  5^-1  .....so we can write

(5²)^x   =  5^-1

5^2x  = 5 ^-1         since the bases are the same, we can equate exponents

2x  = -1              divide both sides by 2

x  =  -1/2

Also..

5 * 4 * (3 - 2 - 1)

If you want to keep them in that order. 

                                                   3​         11          18          33         65         123            216

Frst differences                               8           7           15          32          58             93

Second differences                                -1          8           17           26          35

Third differences                                         9             9            9            9

Since we have   a constant difference in the third differences, this series can be represented by a cubic polynomial =

an^2   +  bn^2  + cn  + d           where   "n"  is  is the nth value of the sequence

We have that

a      +      b       +      c      +     d     =    3      →  -a   - b   - c  - d   =  -3      (1)

8a    +    4b       +   2c       +     d     =   11      (2)

27a  +    9b       +   3c       +    d      =   18      (3)

64a  +    16b    +    4c       +    d      =   33      (4)

Add (1) and (2),   (1) and (3)   and  (1)  and (4)....and we have

7a    +  3b  +  c     =  8      (5)

26a  +  8b  +  2c   =  15    (6)

63a  + 15b  + 3c  =  30     (7)

Multiply   (5)  by -2 add it to (6)    and    (5)  by -3 and  add it to (7) 

And we have

12a  + 2b  =  - 1      (8)

42a  + 6b  =   6        (9)

Multiply  (8)  by  - 3 and add it to (9)

6a   =  9       →    a   = 9/6  = 3/2

And   to find b we have that       12 (3/2)  + 2b  = - 1   →   2b  = -19 →  b  = -19/2

And to find c we have  7(3/2) + 3(-19/2)  + c  = 8  →  -36/2  + c  = 8  → 

-18 + c  = 8       →  c  = 26

And to find d  we have that

(3/2)  + (-19/2)  +  26  + d   = 3

-16/2   +  26  + d   = 3

-8 +  26  +  d  = 3

18  + d  = 3

c  = -15

So....our generating  function is     (3/2)n^3  - (19/2)n^2  + 26n  -  15

Rosy  left for the summer to visit relatives in Ireland......whether, or not,  she made it back, I don't know.....

She was also in an area of Florida that was affected by Hurricane  Irma....don't know the story there, either.....

22.30  - (.25)  + 1.25  =  $ 23.30

It's a window!

Well, I am going to answer anyway.

Absolute value inequalities are not that simple! You can't simply just ignore them.

This is your answer. Since the greater than symbol will cause an "or" statement, we know that solutions are the following:

\(x>\frac{17}{7}\hspace{1mm}\text{or}\hspace{1mm} x<-\frac{117}{7}\)

Here's another solution!

\(4^{2+3-5}-1=0\)

\(4^2-5*3-1=0\)

\(\frac{4*3}{2}-5-1=0\)

\(\frac{4+1}{5}-3+2=0\)

These are a few possibilities that I came up with.

It's high noon.

well, the way you calculate it is pretty simple you know that 375 is 75% of the original prize so you divide it with 75% instead of a 100% because then you will get what 1% of the original prize then you just multiply it by 100 and then you get the original prize

which is = 500 dollars

I hope this helped you out -Mathowl

Simplify the following logical expression using the Laws of Logic.

(¬p ∨ ¬q V r) → ¬ (q ∨ r) = ¬r ∧ ( p ∨ ¬q )

She has not posted anything since 26th May 2017  :(

a cylindrical tank is 8 meters long and 4 meters in diameter.

How many liters of liquid will the tank hold?

Let d = Diameter of the cylindrical tank = 4 meters
Let r = Radius of the cylindrical tank \(\mathbf{= \frac{d}{2}=\frac{4}{2} = 2\, meters}\)
Let h = Height of the cylindrical tank = 8 meters
Let V = Volume of the cylindrical tank

\(\begin{array}{|rcll|} \hline V &=& \pi r^2 h \\ &=& \pi\cdot 2^2 \cdot 8\ m^3 \\ &=& 32\pi \ m^3 \\ &=& 100.530964915\ m^3 \\ &=& 100.530964915\ m^3 \times \frac{1000\ l}{1\ m^3} \\ &=& 100.530964915 \cdot 1000\ \text{liters} \\ &=& 100530.964915\ \text{liters} \\ \hline \end{array}\)

The Tank will hold 100531 liters

factorise 8x-12

\(8x-12 \\ = 2*4*x-3*4 \\ = 4*(2x-3) \)

find the following sum

Use​ Gauss's approach to find the following sum​ (do not use​ formulas):

4+9+14+19+...+59.

The sum of the sequence is ?

\(\tiny{ \begin{array}{rcccccccccccccccccccccccc} && 4&+& 9&+&14&+&19&+&24&+&29&+&34&+&39&+&44&+&49&+&54&+&59 \\ &(reverse)& 59&+&54&+&49&+&44&+&39&+&34&+&29&+&24&+&19&+&14&+& 9&+& 4 \\ \hline &(sum)& 63&+&63&+&63&+&63&+&63&+&63&+&63&+&63&+&63&+&63&+&63&+&63 \\ \end{array} } \)

The sum of the sequence is \(\mathbf{\frac{ 12 * 63}{ 2}=378}\)

Don't have to answer I already got the answer :)