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What answer are you looking for?

This is given by

32(1.5)^n-1    where n is the nth term

Uh.......19  ???

y=-3x^2-6x+4

Letting b = -6  and a = -3.....the x coordinate of the vertex is given by

-b/[2a]  =  -(-6)/ [2(-3)]  = 6/-6  = -1

And to find y, put this value back into the function

y = -3(-1)^2 -6(-1) + 4  =  -3 + 6 + 4  = 7

-------------------------------------------------------------------------------------------------

x-5=20 x=15

Well

$$5^2 = 25$$

$$6^2 = 36$$

Which means

$$\sqrt{25} = 5$$

$$\sqrt{36} = 6$$

Hence for any number

$$5 < c < 6$$

$$\sqrt{25} < \sqrt{c} < \sqrt{36}$$

Therefore the only correct answer is

$$a.) \sqrt{28}$$

wow i cant believe this...two morons.. the answer is 2

A woodchuck could chuck as much wood as a woodchuck could chuck if a woodchuck could chuck wood.

We find that the radius is half the diameter. Therefore if the diameter is 3.1 meters the radius must be 1.55 meters.

$$1 \frac{1}{2} = \frac{3}{2}$$

$$\frac{{(\frac{3}{2})}}{2} = \frac{3}{2 \cdot 2} = \frac{3}{4}$$

or

$$1\frac{1}{2} = 1.5$$

$$\frac{1.5}{2} = 0.75$$

double post (to be deleted)

We can solve it in this way

$$\begin{array}{lcl}
9^x 3^4 = 3^{10}\\
(3^2)^x 3^4 = 3^{10}\\
3^{2x} 3^4 = 3^{10}\\
3^{2x+4} = 3^{10}\\
2x+4 = 10\\
2x = 6\\
x = 3\\
\end{array}$$

$$\sqrt{25} = 5 \text{ since } 5 \cdot 5 = 25$$

$$(3\sqrt{3})^2 = 3^2 * \sqrt{3}^2 = 9 * 3 = 27$$

I'm not sure whether wood can chuck, but I hope you wooed chuck into chucking wood

Note that there is no single solution for this question since there are 2 variables and only 1 equation. However we do find that the equation is given by

$$5q - 9 = r$$

or similarly

$$q = \frac{r+9}{5}$$

Reinout

First we solve the equation for y

$$\begin{array}{lcl}
x - y = x + y + 17\\
-y = y + 17\\
-2y = 17\\
y = -\frac{17}{2}
\end{array}$$

We have 2 possible situations for x

either 

$$\begin{array}{lcl}
y = -\frac{17}{2}\\
\end{array}$$

and we find

$$\begin{array}{lcl}
x - y = x + y + 17\\
x + \frac{17}{2} = x - \frac{17}{2} + 17\\
x = x - 17 + 17\\
x = x
\end{array}$$

Which means x can be any number,

or

$$\begin{array}{lcl}
y \neq -\frac{17}{2}\\
\end{array}$$

and we find no value for x for which the equation holds.

Reinout

Here's how I solved it

$$\begin{array}{lcl}
e = 2\frac{1}{2} = \frac{4}{2} + \frac{1}{2} = \frac{5}{2}\\
f = 3\frac{1}{3} = \frac{9}{3} + \frac{1}{3} = \frac{10}{3}\\
4e-2f = 4*\frac{5}{2} - 2*\frac{10}{3}\\
= \frac{20}{2} - \frac{20}{3}\\
= \frac{20}{2} * 1 - \frac{20}{3} * 1\\
= \frac{20}{2} * \frac{3}{3} - \frac{20}{3} * \frac{2}{2}\\
= \frac{60}{6} - \frac{40}{6}\\
= \frac{60-40}{6}\\
= \frac{20}{6}\\
= \frac{10}{3}\\
= 3 \frac{1}{3}
\end{array}$$

Reinout 

it is the same as asin

[2nd]  [asin]

y=2x-3

 4x-2y=5  

4x-2(2x-3)=5

4x-4x+6=5

6=5

Obviously not correct - there ar no solutions.

Now lets see if we vcan work out why.  

y=2x-3      This is a line and the gradient is 2  and a y intercept of -3

4x-2y=5

-2y=-4x+5

y=2x-(5/2)        This is a line with a gradient of 2 and a y intercept of -5/2

Since these 2 lines have different y intercepts but equal gradients they must be parallel lines.

Parallel lines never cross

therefore they have NO simultaneous solutions.    :)

@@ End of Day Wrap    Wed 25/3/15   Sydney, Australia    Time 10:50 pm   ♪ ♫

Hi all,

Today our fabulous answerers were Nauseated, Alan, Geno3141, Bertie, Reinout-g, Linkfan12, BVBRebel, Mathrulz, Civonamzuk, CowgirlAMS, Leonaofwales. and Fieldmouse830.  Thanks so much. 

Interest Posts:

Thurs 26/3/15

Thanks Alan,

That is a super neat pic in that article !!