Add the two equations together to get

2x = 8/12

x = 4/12

from the first equation then  4/12 + y = 7/12   means y = 3/12

then    (4/12)^2 - (3/12)^2  =   (1/3)^2 - (1/4)^2 = 1/9 - 1/16  = 16/144 - 9/144 = 7/144

[-3,7)

-3 is equal to or less than x so there for it is infinate    [

7 is grater than x so there for it is not infinite   )

edit

woops ep beat me

sorry do not know this

x can be EQUAL to or greater than  -3   sooo    [-3

   and is less (but does no inlude) + 7     soooo    7)

     put them together:   [-3,7)

the answer would be 2.5 or if you would like the exact answer 2.429

edit

sorry did not read question it would be 2 seconds at 28 meters

If you buy a rooster for the purpose of laying eggs and you expect to get three eggs each day for breakfast, how many eggs will you have after three weeks?

the rooster is a male chicken so if you buy a rooster for eggs you will have seamen for breakfest

aka seamen is male fertilizer(spe*rm)

for the young girls sorry for the inaproprite context

Travisio

Edit

Also you would have to have a hen to get eggs

🐔=🐣   🐓=🍥

sorry thats the closest i could get to an egg or an empty plate

i dont get it electric pavlov

I believe that this probability  is just the ratio of the volume of a sphere with a radius of 1 inscribed in  a cube with a side of 2

So.....we have that

(4/3)pi (1)^3            (4/3) pi          4 pi            pi

__________  =     _______  =   _____  =   ____ ≈    .5236   ≈   52.36 %

    2^3                         8                 24              6

kx + y + 3z  = 10      multiply through by -2 ⇒  -2kx - 2y - 6z  =  -20      (1)

-4x + 2y + 5z  = 7   (2)

kx + z  = 3     (3)

Add (1) and (2)   and we have that

-(2k + 4)x  - z  =  -13     multiply through by -1    ⇒    (2k + 4)x  + z =  13      (4)

Note that   if      (2k + 4)  =  k,  then the system will have no solutions

So

2k + 4  = k

k  = - 4

This will be a parabola  that turns upward

To find the x coordinate of the vertex we have that    (k -3) / 2

So

[(k - 3) /2]^2  - (k -3) (k - 3)/2 - k + 6 > 0

( k^2 - 6k + 9 ] / 4   - ( k^2 - 6k+ 9)/2  - k + 6 > 0      multiply through by 4

k^2 - 6k + 9  -  2(k^2 - 6k + 9)  - 4k + 24 > 0

k^2 - 6k + 9  - 2k^2 + 12k - 18 - 4k +  24 > 0

-k^2  + 2k  + 15 > 0         mutiply through by -1 and reverse the inequality sign

k^2 - 2k - 15  < 0  factor

(k - 5) ( k + 3) < 0

We have three possible intervals that solve this

(-infinity, -3)   or  ( - 3, 5)   or  ( 5, infinity)

The outside intervals do not provide the correct solution

So.....the interval   k = (-3, 5)   is correct   

Amplitude  =  (highest - lowest)/2 = 6 - -6  /2  = 12/2 = 6 feet

period = time for 1 cycle   from high to low to high = 6 + 6 = 12 hours

frequency = 1/period   = 1/12   cycles per hour

midline = 0  (midpoint between high and low)

Vertical shift = 0    the high and the low are equal in magnitude

Phase shift = 0 if using cosine function to model this     or  90 degrees  (pi/2) leftward if using sine

Usual cos period is 2pi

    we want 1/12 of the        1/12 x 2pi = pi/6  

              6 cos ( (pi/6) *x) = height    or     6 sin ((pi/6)( x) + pi/2))

6 cos (pi/6 x)    when x = 93    6 cos (93pi/6) = 0 ft

Here is the graph:

https://www.desmos.com/calculator/3pv8ltv8xh

I'm how to do this but this is my best shot. So first, you can think of it as a quadratic. So simplifying the expression you get \(x^2-kx-3x-k+6>0\)  

Using the quadratic formula, you get \(\frac{-(-k+3) \sqrt {(-k-3)^2-4(6-k)}}{2} > 0\)

simplify, \(\frac{k-3\sqrt{k^2+6x+9-24+4k}}{2} = \frac{k-3\sqrt{k^2+10x-13}}{2} > 0\)

I hope that helped, i just kind of bashed it out, now i hope you can solve it. I dont really know how to myself. Sorry if this post was no help at all :( 

-Evan 

Here :  https://web2.0calc.com/questions/help-please_10141

Using just the on-site calculator:   Is that 2 divided by sqrt 7?

(5+(2/sqrt(7)))^4 = 1097.6444772902544618   ~~ 1098

If it is 2 * sqrt 7:

(5+(2*sqrt7))^4 = 11217.9927794569320519  ~~ 11218

No big deal, KLP.....we both got the correct answer.....I gave you a point, too !!!

\($(5+2\sqrt7)^4$ \)      using the binomial expansion

C(4,0) *5^4  +  C(4,1) * (5)^3 * (2√7)  +  C(4,2) * (5^2) * (2√7)^2  +  C(4, 3) * (5) (2√7)^3  + C(4, 4)*(2√7)^4  =

625  +  4 * (125) * 2√7  +  6 * 25 * 4*7  +  4 *5 * (8 ) *(√7)^3  + 2^4 * (√7)^4  =

625  +  1000√7  + 4200 +  160* 7 * √7  + 16 * 49  =

625 + 1000√7 + 4200 + 1120√7 + 784  =

5609  + 2120√7   ≈   11,218  [ to the nearest integer ]

Annnnnd CPhill beat me to it

Let \(d\) be the distance to location b in km. Since you drove \(100\) km/h, then the time that it took you to get there is \(\frac{d}{100}\). If you drove \(120\) km/h then the time would be \(\frac{d}{120}\). Since you drove arrived \(55 \) minutes later, and \(\frac{55}{60}\), or \(\frac{11}{12}\). Therefore we can create the equation, \(\frac{d}{120}=\frac{d}{100}-\frac{11}{12}\). Multiplying both sides by \(600\). The LCM. We get \(5d=6d-550\). Subtract \(6d\) from both sides. \(-d=-550\). Divide by \(-1\). \(d=550\). The distance between location \(a\) and location \(b\) is \(550\) km.

-\(\pi\) KeyLimePi

Remember that Rate * Time = Distance

Let the normal driving time  be, T  (in hours)

Let 15 min  = (1/4)hr

Let 40 min  = (2/3)hr

So....equating distance betwen a and b, we have that

100 * ( T + 1/4)   =   120 * ( T - 2/3)      simpify

100T + 25  =  120T  - 80       add 80 to both sides , subtract 100T from both sides

105  =  20T         divide both sides by 20

105 / 20  = T   =  5.25 hrs

So....the total distance between a and b is  

100 * ( 5.25 + 1/4)   =   100 (5.25 + .25 )  = 100 (5.50)  =  550 km

10x + 25x^4       take out the GCF  =  5x

5x ( 2 + 5x^3)

Oh, okay. Thanks for the help!!!

Yes I see Thanks Melody (; 

Yes I see Thanks Melody 

   THAT is funny!   I agree.....seems asker is in a bit over her/his head with this level of math !   ~EP