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Use the fact that \(cos(x)=2cos^2(x/2)-1\)

Like so:

oops set up the graphs wrong ty i was so confused

Guest, I am sorry to hear that.

It is clear that your first statement is correct, and it is my mistake that I have not gone over the question carefully.

HOWEVER,

I have checked at the original site whether my answer is correct, and I have come to the conclusion that it is. If you are making fun of it because I have not directly included the answer, than I have nothing to say for you but answer-dependent. Otherwise, you will have to convince me that my process of solution is wrong.

Finally, I have a picture of my work of all the angles marked out accordingly to the given statements. I have confirmed repeatedly, and unless you can give convincing reasons to use the word ATROCIOUS and the Field MeTal, I will have to flag your response in the name of mis-accusing.

The picture is here:

The original site, in case you forgot it, is here: https://web2.0calc.com/questions/help-with-geometry_125

Hi Ron,

If you want to use spaces to align ASCII text in HTML documents, the first requirement is to be smarter than your computer.  LOL

Seriously, using spaces to align ASCII text in HTML documents is often an exercise in futility.

Here are some useful equations:

I'll let you fill in the numbers.

Height = h

(4+h)² - h² = 12²

h = 16

P = 24 + 2(4+16)

A = 1/2(24*16)

A triangular region is enclosed by the lines with equations 1) y = 1/2 x + 3, 2) y = -2x + 6 and 3) y = 2. What is the area of the triangular region? Express your answer as a decimal to the nearest hundredth.

Hello Guest

\(P_{1,2}\\ \frac{1}{2}x+3=-2x+6\\ x=\frac{6}{5}\\ y=3.6\)

\(P_{1,3}\\ 0.5x+3=2\\ x=-2\\ y=2\)

\(P_{2,3}\\ -2x+6=2\\ x=2\\ y=2\)

\(A=(2-(-2))\cdot (3.6-2)/2\)

\(A=3.2\)

  !

There is no solution for this question as stated. 

The sum of two included angles (BMC + angle B) of a triangle has to be less than 180° The question states the sum of 201° for these angles.

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there is also the option

sin x+cosx/cosx sin x 

it was cropped out at the bottom 

sorry it says 

Angle x is a third quadrant angle such that cosx= -1/5

what is the exact value of cos(x/2)

enter your answer in the simpliest radical form 

More information please.

Simplify to get 10/3t <= 12,

we isolate t to get t <= 18/5, and finish off with the interval notation.

the p is right but note that the 30 is outside of the square root.

See my response here: https://web2.0calc.com/questions/help-with-geometry_125

Please note the question is slightly different at the end but the steps are literally identical

Very important text:

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Keith and Lucas each had a mix of twenty-cent and one-dollar coins. Keith had 16 one-dollar coins...

(c) Keith used half of his one-dollar coins and some of his twenty-cent coins to buy a book that cost $10.40. Then, he had 7/10 of his twenty-cent coins left. How many twenty-cent coins did Keith have at first?

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1/  Keith had 16 one-dollar coins                                                                   => 16 coins

2/  He spent 8 one-dollar coins and 12 twenty-cent coins to buy a book.     =>  12 coins

3/  After he bought a book, Keith had 7/10 of his twenty-cent coins left.       =>  28 coins

12 / (3/10) = x / (7/10)         x = 28

Keith had 40 twenty-cent coins and 16 one=dollar coins.

Remember, all 3 boys had an equal number of coins. 

x - x/4 - 1/5(3x/4) = 240

x = 400

xy = 10 

B = (5, 2) 

$\sqrt{25}=5$

$\sqrt{72}=\sqrt{4\cdot9\cdot2}=6\sqrt2$

so $\frac{\sqrt{72}}{\sqrt{25}}=\boxed{\dfrac{6\sqrt2}{5}}$

The answer is $p \sqrt{30p}$.

Interior angles    (n-2)* 180       Exterior angles sum to 360

(n-2)*180 /360 = 2. 5

n=7